Electrochemistry

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Electrochemistry - 04

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Q1. The cell constant of a conductivity cell ___________ *

1 point

changes with change of electrolyte.

changes with temperature of electrolyte.

changes with change of concentration of electrolyte.

remains constant for a cell

Q2. Kohlrausch’s law states that at *

1 point

infinite dilution, each ion makes definite contribution to equivalent conductance of an electrolyte, whatever be the nature of the other ion of the electrolyte.

finite dilution, each ion makes definite contribution to equivalent conductance of an electrolyte, whatever be the nature of the other ion of the electrolyte.

infinite dilution, each ion makes definite contribution to conductance of an electrolyte whatever be the nature of the other ion of the electrolyte.

infinite dilution each ion makes definite contribution to equivalent conductance of an electrolyte depending on the nature of the other ion of the electrolyte.

Q3. Which of the following expressions correctly represents the equivalent conductance at infinite dilution of Al2(SO4)3, *

1 point

Q4. Molar conductivities (/qm) at infinite dilution of NaCl, HCl and CH3COONa are 126.4, 425.9 and 91.0 S cm2 mol–1, respectively. Molar conductivity for CH3COOH will be *

1 point

180.5 S cm2 mol–1

425.5 S cm2 mol–1

390.5 S cm2 mol–1

290.8 S cm2 mol–1

Q5. Molar ionic conductivities of a two-bivalent electrolytes X^+2 and Y^-2 are 57 and 73 respectively. The molar conductivity of the solution formed by them will be *

1 point

65 S cm2 mol–1

130 S cm2 mol–1

260 S cm2 mol–1

187 S cm2 mol–1

Q6. On electrolysis of dilute sulphuric acid using platinum electrodes, the product obtained at the anode will be *

1 point

hydrogen sulphide

Sulphur dioxide

hydrogen

oxygen

Q7. If 0.5 amp current is passed through acidified silver nitrate solution for 100 minutes. The mass of silver deposited on cathode, is (eq.wt.of silver nitrate = 108) *

1 point

2.3523 g

6.3575 g

3.3575 g

5.3578 g

Q8. Which of the following is the use of electrolysis? *

1 point

(a) Electrorefining

(b) Electroplating

(d) None of these

Q9. When 9650 coulombs of electricity is passed through a solution of copper sulphate, the amount of copper deposited is (given at. wt. of Cu = 63.6) *

1 point

0318 g

3.18 g

31.8 g

63.6 g

Q10. A silver cup is plated with silver by passing 965 coulombs of electricity. The amount of Ag deposited is *

1 point

1.08 g

9.89 g

1.0002 g

107.89 g

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