Some basic principles of organic chemistry (GOC)

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Isomerism- Test1 Max. Marks = 40

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1. Which one of the following pairs are called position isomers –

4 points

(A) CH₂(OH)CH₂COOH & CH₃-CH(OH)COOH

(B) C₂H₅OH & CH₃OH

(D) All theabove

Clear selection

2. Methyl propyl thioether and isopropyl methyl thioether are –

4 points

(A) Metamers

(B) Position isomers

(D) Chain and position both

Clear selection

3.The formula C₄H₈O₂ represents –

4 points

(A) Only an acid

(B) Only an ether

(D) Both ether and alcohol

Clear selection

4. Urea and thiourea exhibits -

4 points

(A) Metamerism

(B) Tautomerism

(D) Geometrical isomerism

Clear selection

5. Geometrical isomerism is due to -

4 points

(A) The resticted rotation about a double bond

(B) The presence of keto group

(D) The presence of an asymmetric carbon

Clear selection

4 points

(A)

(B)

(C)

(D)

Clear selection

7.How many asymmetric carbon atoms are present in -

(i) 1,2-dimethyl cyclohexane

(ii) 3-methyl cyclopentene

(iii) 3-methyl cyclohexene

4 points

(A) Two, one, one

(B) One, one one

(D) Two, none, one

Clear selection

8. The number of geometrical isomers in the following compound,

CH₃–CH = CH–CH=CH–C₂H₅ is -

4 points

(A) 4

(B) 3

(D) 5

Clear selection

9.The total number of secondary alcohols (including stereoisomers) possible having the molecular formula C₅H₁₂O is -

4 points

(A) 3

(B) 4

(D) 6

Clear selection

10. Among the following compounds, the one which is not isomeric with t-pentyl alcohol is –

4 points

(A) 3-methyl-1-butanol

(B) 2-methyl-1-butanol

(D) 2-methyl-2-butanol

Clear selection

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