Chapter - Solution (4) Objective Type, Based on Raoult's Law

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Q1. What is the vapor pressure of an aqueous solution that has a solute mole fraction of 0.1000? The vapor pressure of water is 25.756 mmHg at 25 °C. *

1 point

40.65 mm Hg

12.25 mm Hg

23.18 mm Hg

5.18 mm Hg

Q2. The vapor pressure of an aqueous solution is found to be 24.90 mmHg at 25 °C. What is the mole fraction of solute in this solution? The vapor pressure of water is 25.756 mm Hg at 25 °C. *

2 points

0.05

0.09

0.01

0.03

Q3. How many grams of nonvolatile compound B (molar mass= 97.80 g/mol) would need to be added to 250.0 g of water to produce a solution with a vapor pressure of 23.756 torr? The vapor pressure of water at this temperature is 42.362 torr. *

3 points

1063 gms

1250 gms

980 gms

867 gms

Q4. The vapor pressure of pure water is 23.8 mmHg at 25.0 °C. What is the vapor pressure of 2.50 molal C6H12O6? *

3 points

10.5 mm Hg

5.86 mm Hg

22.8 mm Hg

30.8 mm Hg

Q5. For the Solutions having +ve deviations from Raoult's law have - *

1 point

V.P. = χAP0A + χBP0B

V.P. < χAP0A + χBP0B

V.P. > χAP0A + χBP0B

None of them

Q6. On additon of Non Volatile solute in a solvent, The vapour pressure of Solvent - *

1 point

Decreases

Increases

Does not change

None of them

Q7. Which of the following aqueous solutions should have the highest boiling point? *

1 point

1.0 M NaOH

0.75 M Na2SO4

0.75 M NH4NO3

1.0 M KNO3

Q8. Which one will has maximum lowering in vapour prssure? *

1 point

1 M Urea

1 M Glucose

1 M KCl

1 M Sucrose

Q9. For Ideal Solutions - *

1 point

ΔV mix = O

ΔV mix ≠ O

ΔH mix ≠ O

None of them

Q10. For a solution showing -ve deviation from Raoult's law has - *

1 point

ΔV mix = O

ΔV mix < O

ΔV mix > O

None of the above

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