Year 8 Simple Quadratic Equations

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Solve the equation x² = 16

1 point

x = ±4

x = ±16

x = ±8

x = ±256

Clear selection

The solution of x² = 4 is

1 point

x = 2

x = ±2

x = 16

x = 0 and 2

Clear selection

Solve the equation x² = 12100

1 point

x = 110

x = ±121

x = ±110

x = 0 and 110

Clear selection

Solve the equation –x² = –49

1 point

No solution

x = ±49

x = 7

x = ±7

Clear selection

Solve the equation 3x² = 27

1 point

x = 3

Option 2

x = ±3

x = ±9

Clear selection

Solve the equation (x+3)² = 16

1 point

x = -4 and 4

x = -1 and 1

x = -1 and 7

x = -7 and 1

Clear selection

A student solved the equation x² = 132 to find the length of the diagonal of a square in centimetres. Which measurement is closest to x, the length of the diagonal of this square, in centimetres?

1 point

66 cm

44 cm

33 cm

11 cm

Clear selection

Solve for 𝑘 in 𝑘² = 36

1 point

±4

±6

±9

±12

Clear selection

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