Year 10 Equations with Brackets

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The best first step in solving the equation 7(x − 6) = 23 would be to:

1 point

add 6 to both sides

subtract 7 from both sides

divide both sides by 23

expand the grouping symbols

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The solution of 3(u + 1) = 15 is:

1 point

u = 4

u = 5

u = 11

u = 6

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The solution to the equation −3(m +4) = 9 is:

1 point

m = 7

m = -7

m = 1

m = -1

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Solve −3(d + 4) = 21.

1 point

d = -12

d = -11

d = -9⅓

d = 3

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The solution to the equation 84(x − 21) = 782 is:

1 point

x = 9.31

x = 9.56

x = 30.31

x = −11.69

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Solve 4(a + 6) = 18.

1 point

a = 1½

a = -1½

a = ⅔

a = −⅔

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Solve 6(u + 2) = 4(u + 15).

1 point

u = 24

u = 36

u = 96

u = 26

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State the value of f in the equation 6(2f − 7) = 2(4f + 8).

1 point

14.5

3.75

12.5

10.25

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Which of the following is the solution to the linear equation 5(2x − 3) − 4(2x + 3) = 0?

1 point

x = −13.5

x = 13.5

x = −0.944

x = 0.944

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The equation 3(2n + 9) = 45 can be solved by:

1 point

subtracting 9 from both sides, then dividing by 3, finally dividing by 2

dividing by 3 then dividing by 2, finally subtracting 9 from both sides

dividing by 3 then subtracting 9 from both sides, finally dividing by 2

dividing by 2 then subtracting 9 from both sides, finally dividing by 3

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