Questionnaire 12

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Questionnaire 12

Open until 27.6.23, 08:00

Name: *

ID: *

Given the two signals:

P(t)=A*sin(20*pi*t+a) Q(t)=B*sin(20*pi*t+b)

The coherence between the two signals...

25 points

At peak at 20 Hz with amplitude depends on A & B and the phase depends on a & b.

At peak at 20 Hz where the amplitude doesn't depend on A & B and the phase doesn't depend on a & b.

At peak at 10 Hz where the amplitude dpends on A & B and the phase depends on a & b.

At peak at 10 Hz where the amplitude doesn't depend on A & B and the phase doesn't depend on a & b.

Two analog signals Q=7sin(2*pi*5t+0.2*pi) and P=3sin(2*pi*7t+0.5*pi) are recorded. What will be the PSD of each signal look like?

25 points

Peak in 7 Hz with power of 5 for Q, peak in 3 Hz with power of 7 for P

Peak in 5 Hz with power of 7 for Q, peak in 7 Hz with power of 3 for P

Peak in 5 Hz with power of 49 for Q, peak in 7 Hz with power of 9 for P

Peak in 49 Hz with power of 5 for Q, peak in 9 Hz with power of 7 for P

Mr. Salinger wants check a possible phase locking on a signal with the frequencies of 5,14,80 Hz. What would you recommend him to do?

25 points

Run Hilbert transformation on the full signal

Running three times Hilbert transformation after using notch filter for two frequencies

Running three times Hilbert transformation after using high pass filter

Not enough information about the relations wights of each frequency in the signal

A signal Z=10sin(2*pi*500t+pi) is manipulated in two ways.

1. The signal is filtered using a perfect 200 Hz analog low pass filter and afterwards sampled at 200 samples/second.

2. The signal is sampled at 200 samples/second and afterwards filtered using a perfect 200 Hz digital low pass filter.

What is the difference in the PSD of the resulting signals?

25 points

no peaks in the first way, peak at 100 Hz in the second

peak at 50 in the first way, peak at 100 Hz in the second

peak at 50 in the first way, peak at 50 Hz in the second

peak at 100 in the first way, no peaks in the second

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