Chemical Bonding

Name *

School Name *

Mobile No. (without +91) *

1. Geometry of the molecule is distorted VSEPR in-

(I) H₂O (II) NH₃ (III) N₃H (IV) XeF₂

4 points

(A) I, III, IV

(B) II, III, IV

(C) I, II, III, IV

(D) I, II

Clear selection

2. In an antibonding molecular orbital, electron density is minimum -

4 points

(A) Around one atom of the molecule

(B) Between the two nuclei of the molecule

(C) At the region away from the nuclei of the molecule

(D) at no place

Clear selection

3. T-type of shape is exhibited by the molecule

4 points

(A) ICl₃

(B) CHCl₃

(C) CCl₄

(D) PCl₅

Clear selection

4. In terms of polar character, which of the following order is correct ?

4 points

(A) NH₃ < H₂O < HF < H₂S

(B) H₂S < NH₃ < H₂O < HF

(C) H₂O < NH₃ < H₂S < HF

(D) HF < H₂O < NH₃ < H₂S

Clear selection

5. Of the following compounds, which will have a zero dipole moment ?

4 points

(A) 1, 1-dichloroethylene

(B) cis-1, 2-dichloroethylene

(C) trans 1, 2-dichloroethylene

(D) None of these

Clear selection

6. Which one of the following has the highest bond angle -

4 points

(A) H₂O

(B) H₂S

(C) NH₃

(D) PH₃

Clear selection

7. o-nitrophenol is more volatile than para-nitrophenol due to -

4 points

(A) intramolecular H-bonding in o-nitrophenol and intermolecular H-bonding in p-nitrophenol

(B) intermolecular H-bonding in o-nitrophenol and intramolecular H-bonding in p-nitrophenol

(C) more stronger intramolecular H-bonding in o-nitrophenol as compared to p-nitrophenol

(D) more stronger intermolecular H-bonding in o-nitrophenol as compared to p-nitrophenol

Clear selection

8. Molten sodium chloride conducts electricity due to the presence of :

4 points

(A) Free electrons

(B) Free molecules

(C) Free sodium and chloride atoms

(D) Free sodium and chloride ions

Clear selection

9. Correct order of covalent character of alkaline earth metal chloride in :

4 points

(A) BeCl₂ < MgCl₂ < CaCl₂ < SrCl₂

(B) BeCl₂ < CaCl₂ < SrCl₂ < MgCl₂

(C) BeCl₂ > MgCl₂ > CaCl₂ > SrCl₂

(D) SrCl₂ > BeCl₂ > CaCl₂ > MgCl₂

Clear selection

10. Correct order of polarising power is:

4 points

(A) Cs⁺ < K⁺ < Mg²⁺ < Al³⁺

(B) Al³⁺ < Mg²⁺ < K⁺ < Cs⁺

(C) Mg²⁺ < Al³⁺ < K⁺ < Cs⁺

(D) K⁺ < Cs⁺ < Mg²⁺ < Al³⁺

Clear selection