Year 7 Solving Equations with Brackets

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Year 7 Solving Equations with Brackets

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The solution to 3(a + 1) = 15 is

1 point

a = 5

a = 4

a = 11

a = 6

Clear selection

If 2(7 − x) = 3 then x equals

1 point

x = 11

x = –17

x = 8.5

x = 5.5

Clear selection

Solve 3(x + 2) = 18

1 point

x = 6

x = 4

x = 8

x = 5

Clear selection

Solve 7 = 7(4q - 3)

1 point

q = 7

q = 4

q = 3

q = 1

Clear selection

Solve 3(b + 5) + 4b = 29

1 point

b = 5

b = 4

b = 2

b = 3

Clear selection

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